JEE Main 2023 · 25 January · morning · Single correct · +4 / −1

Reaction of thionyl chloride with white phosphorus forms a compound [A], which on hydrolysis gives [B], a dibasic acid. [A] and [B] are respectively :

  1. (a) P₄O₆ and H₃PO₃
  2. (b) POCl₃ and H₃PO₄
  3. (c) PCl₅ and H₃PO₄
  4. (d) PCl₃ and H₃PO₃
Answer and solution

Answer (d) PCl₃ and H₃PO₃

Solution

Chemistry ma’am · 4 steps

The word dibasic gives it away: that is H₃PO₃, so [A] must be the chloride that hydrolyses to it.

  1. Form [A]. Thionyl chloride chlorinates white phosphorus to phosphorus trichloride. This is the standard NCERT preparation of PCl₃.

    P₄ + 8SOCl₂ → 4PCl₃ + 4SO₂ + 2S₂Cl₂

  2. Hydrolyse [A]. Water replaces each Cl on P: PCl₃ + 3H₂O → H₃PO₃ + 3HCl. So [B] is phosphorous acid, H₃PO₃.
  3. Why dibasic. In H₃PO₃ the phosphorus carries one P=O, two P-OH and one P-H. Only the two O–H hydrogens are ionisable, so it is dibasic. H₃PO₄ has three P–OH groups and is tribasic.
  4. So. [A] is PCl₃ and [B] is H₃PO₃, option (d).

The idea to keep. Basicity of a phosphorus oxoacid counts only the P–OH groups. H atoms bonded directly to P are not ionisable, so H₃PO₃ is dibasic and H₃PO₂ is monobasic.

Answer from the NTA final answer key. Solution by PrepWiser.

Study p-Block Elements — Part II (Group 15-18)

Asked about 110 times in JEE Main since 2020. This question is from 2023.