JEE Main 2024 · 5 April · morning · Single correct · +4 / −1

An organic compound has 42.1 % carbon, 6.4 % hydrogen and remainder is oxygen. If its molecular weight is 342 , then its molecular formula is :

  1. (a) C₁₄ H₂₀ O₁₀
  2. (b) C₁₂ H₂₂ O₁₁
  3. (c) C₁₂ H₂₀ O₁₂
  4. (d) C₁₁ H₁₈ O₁₂
Answer and solution

Answer (b) C₁₂ H₂₂ O₁₁

Solution

Chemistry ma’am · 3 steps

You already know the molar mass, so turn each percentage straight into grams per mole and count atoms.

  1. Oxygen by difference. Oxygen is whatever is left: 100 - 42.1 - 6.4 = 51.5%.

    atoms per molecule = ((% of element) × 342)/(100 × atomic mass)

  2. Count each atom. Carbon: 0.421 × 342 = 144 g, and 144 / 12 = 12. Hydrogen: 0.064 × 342 = 21.9 g, which gives about 22 H. Oxygen: 0.515 × 342 = 176 g, and 176 / 16 = 11.
    OptionMolar mass% C% H
    (a) C₁₄H₂₀O₁₀34848.35.7
    (b) C₁₂H₂₂O₁₁34242.16.4
    (c) C₁₂H₂₀O₁₂35640.45.6
    (d) C₁₁H₁₈O₁₂34238.65.3
  3. So. Only (b) matches both the molar mass and the composition: the formula is C₁₂H₂₂O₁₁, which is sucrose.

The idea to keep. When the molar mass is given, skip the empirical formula. Percentage times molar mass gives grams of each element in one mole, and dividing by atomic mass gives the atom count directly.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Mole Concept & Stoichiometry

Asked about 210 times in JEE Main since 2020. This question is from 2024.