Numerical answer · +4 / −1
The difference in electronegativity between fluorine (4.0) and cesium (0.7) is x × 10⁻¹. Find x.
Answer and solution
Answer 33
No written solution for this question yet.
Numerical answer · +4 / −1
Answer 33
No written solution for this question yet.
Asked about 120 times in JEE Main since 2020.