JEE Main 2024 · 8 April · evening · Single correct · +4 / −1
When ψ_A and ψ_B are the wave functions of atomic orbitals, then σ^* is represented by :
- (a) ψ_A+2 ψ_B
- (b) ψ_A-ψ_B
- (c) ψ_A-2 ψ_B
- (d) ψ_A+ψ_B
Answer and solution
Answer (b) ψ_A-ψ_B
Solution
Chemistry ma’am · 4 steps
Antibonding means the two waves cancel between the nuclei, so you subtract them, with equal weight.
- LCAO idea. A molecular orbital is built by combining atomic orbitals: ψ_(MO) = ψ_A ± ψ_B. Adding gives one orbital, subtracting gives the other.
- Bonding versus antibonding. Addition, ψ_A + ψ_B, makes the waves reinforce between the nuclei. That is the bonding orbital σ. Subtraction, ψ_A - ψ_B, makes them cancel, leaving a node between the nuclei. That is the antibonding orbital σ^*.
σ^* = ψ_A - ψ_B
- Equal weights. The two atoms in this combination contribute equally, so both coefficients have the same size. A factor of 2 on one orbital has no basis here, which rules out (a) and (c).
- So. σ^* is represented by ψ_A - ψ_B, option (b).
The idea to keep. Plus sign means constructive overlap, so bonding. Minus sign means destructive overlap and a node between the nuclei, so antibonding. Keep the coefficients equal for identical atoms.
Answer from the NTA final answer key. Solution by PrepWiser.