JEE Main 2024 · 8 April · evening · Single correct · +4 / −1

When ψ_A and ψ_B are the wave functions of atomic orbitals, then σ^* is represented by :

  1. (a) ψ_A+2 ψ_B
  2. (b) ψ_A-ψ_B
  3. (c) ψ_A-2 ψ_B
  4. (d) ψ_A+ψ_B
Answer and solution

Answer (b) ψ_A-ψ_B

Solution

Chemistry ma’am · 4 steps

Antibonding means the two waves cancel between the nuclei, so you subtract them, with equal weight.

  1. LCAO idea. A molecular orbital is built by combining atomic orbitals: ψ_(MO) = ψ_A ± ψ_B. Adding gives one orbital, subtracting gives the other.
  2. Bonding versus antibonding. Addition, ψ_A + ψ_B, makes the waves reinforce between the nuclei. That is the bonding orbital σ. Subtraction, ψ_A - ψ_B, makes them cancel, leaving a node between the nuclei. That is the antibonding orbital σ^*.

    σ^* = ψ_A - ψ_B

  3. Equal weights. The two atoms in this combination contribute equally, so both coefficients have the same size. A factor of 2 on one orbital has no basis here, which rules out (a) and (c).
  4. So. σ^* is represented by ψ_A - ψ_B, option (b).

The idea to keep. Plus sign means constructive overlap, so bonding. Minus sign means destructive overlap and a node between the nuclei, so antibonding. Keep the coefficients equal for identical atoms.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 210 times in JEE Main since 2020. This question is from 2024.