JEE Main 2024 · 4 April · morning · Numerical answer · +4 / −1
Number of molecules/species from the following having one unpaired electron is ________.
O₂, O₂⁻¹, NO, CN⁻¹, O₂²⁻
Answer and solution
Answer 2
Solution
Chemistry ma’am · 3 steps
Count total electrons, then see how many sit in the two π^* orbitals. That decides everything here.
- Count electrons. Add the electrons of both atoms, then adjust for charge. Each negative charge adds one electron.
- Find the frontier. For 14 electrons, every bonding orbital up to π 2p is full. Electrons 15 to 18 go into the two degenerate π^* 2p orbitals, one in each first (Hund's rule) and then pairing up.
Species Total electrons Electrons in π^* 2p Unpaired O₂ 8 + 8 = 16 ↑ ↑ 2 O₂⁻ 16 + 1 = 17 ↑↓ ↑ 1 NO 7 + 8 = 15 ↑ 1 CN⁻ 6 + 7 + 1 = 14 empty 0 O₂²⁻ 16 + 2 = 18 ↑↓ ↑↓ 0 - So. Only O₂⁻ and NO have exactly one unpaired electron, so the answer is 2.
The common slip: 3. Counting every paramagnetic species, including O₂, gives 3. But O₂ has two unpaired electrons, not one.
The idea to keep. For diatomics of second-period atoms: 14 electrons means none unpaired, 15 or 17 means one, 16 means two, 18 means none. Just count the electrons in π^*.
Answer from the NTA final answer key. Solution by PrepWiser.