JEE Main 2024 · 5 April · morning · Single correct · +4 / −1

The reaction at cathode in the cells commonly used in clocks involves.

  1. (a) oxidation of Mn from +2 to +7
  2. (b) reduction of Mn from +4 to +3
  3. (c) oxidation of Mn from +3 to +4
  4. (d) reduction of Mn from +7 to +2
Answer and solution

Answer (b) reduction of Mn from +4 to +3

Solution

Chemistry ma’am · 4 steps

A clock cell is a dry cell, and its cathode turns MnO₂ into MnO(OH), so Mn drops from +4 to +3.

  1. Which cell. Clocks, torches and remotes use the dry cell (Leclanché cell). Its anode is a zinc container, and its cathode is a carbon rod packed in a paste of MnO₂ and carbon.
  2. Cathode reaction. The cathode always gains electrons, so the reaction there is a reduction. In the dry cell, manganese dioxide is the species that gets reduced.

    MnO₂ + NH₄⁺ + e⁻ → MnO(OH) + NH₃

  3. Oxidation states. In MnO₂, Mn is +4. In MnO(OH) the oxygens give -2 - 1 = -3, so Mn is +3. One electron is gained per Mn.
  4. So. The cathode reaction is the reduction of Mn from +4 to +3, which is option (b).

The idea to keep. Cathode means reduction, every time. For the dry cell, remember the pair MnO₂ → MnO(OH): Mn goes from +4 to +3.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 170 times in JEE Main since 2020. This question is from 2024.