JEE Main 2024 · 5 April · morning · Single correct · +4 / −1
The reaction at cathode in the cells commonly used in clocks involves.
- (a) oxidation of Mn from +2 to +7
- (b) reduction of Mn from +4 to +3
- (c) oxidation of Mn from +3 to +4
- (d) reduction of Mn from +7 to +2
Answer and solution
Answer (b) reduction of Mn from +4 to +3
Solution
Chemistry ma’am · 4 steps
A clock cell is a dry cell, and its cathode turns MnO₂ into MnO(OH), so Mn drops from +4 to +3.
- Which cell. Clocks, torches and remotes use the dry cell (Leclanché cell). Its anode is a zinc container, and its cathode is a carbon rod packed in a paste of MnO₂ and carbon.
- Cathode reaction. The cathode always gains electrons, so the reaction there is a reduction. In the dry cell, manganese dioxide is the species that gets reduced.
MnO₂ + NH₄⁺ + e⁻ → MnO(OH) + NH₃
- Oxidation states. In MnO₂, Mn is +4. In MnO(OH) the oxygens give -2 - 1 = -3, so Mn is +3. One electron is gained per Mn.
- So. The cathode reaction is the reduction of Mn from +4 to +3, which is option (b).
The idea to keep. Cathode means reduction, every time. For the dry cell, remember the pair MnO₂ → MnO(OH): Mn goes from +4 to +3.
Answer from the NTA final answer key. Solution by PrepWiser.