JEE Main 2024 · 27 January · morning · Single correct · +4 / −1

Element not showing variable oxidation state is :

  1. (a) Bromine
  2. (b) Iodine
  3. (c) Chlorine
  4. (d) Fluorine
Answer and solution

Answer (d) Fluorine

Solution

Chemistry ma’am · 3 steps

Fluorine is the most electronegative element, so it never gives up electrons. That leaves it with only -1.

  1. Why fluorine is stuck. Fluorine is the most electronegative element, so no other atom can pull electrons away from it. In every compound it takes one electron and shows only -1. It is 0 only in F₂ itself.
  2. No d orbitals. Fluorine is in period 2, so it has no d orbitals in its valence shell. Its electrons cannot be unpaired and promoted, so it cannot form 3, 5 or 7 bonds the way the other halogens do.
    HalogenVacant d orbitalsOxidation statesExamples
    Fnoneonly -1HF, OF₂
    Clyes (3d)-1, +1, +3, +5, +7HCl, HOCl, HClO₄
    Bryes (4d)-1, +1, +3, +5, +7HBr, BrF₃, HBrO₄
    Iyes (5d)-1, +1, +3, +5, +7HI, ICl, IF₇
  3. So. Chlorine, bromine and iodine all show positive oxidation states with oxygen or fluorine. Fluorine shows only -1, so the answer is (d).

The idea to keep. Among the halogens, only fluorine is fixed at -1. It is the most electronegative element and has no d orbitals, so it can never take a positive oxidation state.

Answer from the NTA final answer key. Solution by PrepWiser.

Study d & f Block Elements

Asked about 170 times in JEE Main since 2020. This question is from 2024.