JEE Main 2022 · 28 June · morning · Single correct · +4 / −1
Stability of α-Helix structure of proteins depends upon
- (a) dipolar interaction
- (b) H-bonding interaction
- (c) van der Waals forces
- (d) π-stacking interaction
Answer and solution
Answer (b) H-bonding interaction
Solution
Chemistry ma’am · 4 steps
In an α-helix, each C=O hydrogen-bonds to the N–H four residues ahead; those bonds hold the coil tight.
- What the helix is. The α-helix is a secondary structure. The polypeptide backbone coils into a right-handed spiral, with about 3.6 amino acid residues per turn.
- What holds it. The C=O of each peptide bond forms a hydrogen bond with the N-H of the residue four places further along the same chain. These bonds run roughly parallel to the helix axis and lock each turn to the next.
- Why not the others. van der Waals forces and dipolar interactions are present but weak and non-specific, so they cannot fix a regular repeating shape. π-stacking needs aromatic rings, and the backbone has none.
- So. The stability of the α-helix comes from intramolecular hydrogen bonding, which is option (b).
The idea to keep. Secondary structures (α-helix and β-pleated sheet) are held by hydrogen bonds between backbone C=O and N-H groups. In the helix they lie within one chain; in the sheet they lie between chains.
Answer from the NTA final answer key. Solution by PrepWiser.