JEE Main 2021 · 27 August · morning · Single correct · +4 / −1

Electric field in a plane electromagnetic wave is given by E = 50 sin(500x - 10 × 10¹⁰ t) V/m The velocity of electromagnetic wave in this medium is :
(Given C = speed of light in vacuum)

  1. (a) 3/2C
  2. (b) C
  3. (c) 2/3C
  4. (d) C/2
Answer and solution

Answer (c) 2/3C

Solution

Physics sir · 3 steps

Read ω and k straight off the sine, divide them, and compare with 3 × 10⁸.

  1. Match the form. A plane wave has the form E = E₀ sin(kx - ω t). Matching terms gives k = 500 m⁻¹ and ω = 10 × 10¹⁰ = 10¹¹ rad s⁻¹.

    v = ω/k = 10¹¹/500 = 2 × 10⁸ m s⁻¹

  2. Compare with C. v/C = (2 × 10⁸)/(3 × 10⁸) = 2/3. The wave is slower than in vacuum, as it should be in a material medium.
  3. So. The speed of the wave in this medium is 2/3C, option (c).

The idea to keep. For any wave written as sin(kx - ω t), the speed is ω / k. The amplitude plays no part in it.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Electromagnetic Waves

Asked about 130 times in JEE Main since 2020. This question is from 2021.