JEE Main 2021 · 27 August · evening · Numerical answer · +4 / −0

A plane electromagnetic wave with frequency of 30 MHz travels in free space. At particular point in space and time, electric field is 6 V/m. The magnetic field at this point will be x × 10⁻⁸ T. The value of x is ___________.

Answer and solution

Answer 2

Solution

Physics sir · 3 steps

In an EM wave, E and B always move together: divide E by c and you have B.

  1. E and B link. In a plane EM wave in free space, the electric and magnetic fields at any point and instant are tied by E = cB. This holds for the instantaneous values, not only the peak values.

    B = E/c = (6 V m⁻¹)/(3 × 10⁸ m s⁻¹) = 2 × 10⁻⁸ T

  2. Frequency not needed. The 30 MHz only sets how fast the fields oscillate. The ratio E/B equals c at every frequency, so the frequency does not enter the calculation.
  3. So. B = 2 × 10⁻⁸ T, so x = 2.

The idea to keep. For any EM wave in vacuum, B = E/c at every point and instant, whatever the frequency. Extra data like frequency is often given just to distract you.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Electromagnetic Waves

Asked about 130 times in JEE Main since 2020. This question is from 2021.