JEE Main 2021 · 27 July · morning · Single correct · +4 / −1

The relative permittivity of distilled water is 81. The velocity of light in it will be :
(Given μᵣ = 1)

  1. (a) 4.33 × 10⁷ m/s
  2. (b) 2.33 × 10⁷ m/s
  3. (c) 3.33 × 10⁷ m/s
  4. (d) 5.33 × 10⁷ m/s
Answer and solution

Answer (c) 3.33 × 10⁷ m/s

Solution

Physics sir · 3 steps

Light slows down in water by the square root of the permittivity, not by the permittivity itself.

  1. Speed in a medium. In vacuum c = 1/√(μ₀ ε₀). In a medium, μ₀ becomes μᵣ μ₀ and ε₀ becomes εᵣ ε₀, so the speed drops by a factor of √(μᵣ εᵣ).

    v = c/√(μᵣ εᵣ)

  2. Put in numbers. With μᵣ = 1 and εᵣ = 81, √(μᵣ εᵣ) = √81 = 9. So v = (3 × 10⁸)/9 m s⁻¹ = 3.33 × 10⁷ m s⁻¹.
  3. So. The velocity of light in distilled water is 3.33 × 10⁷ m s⁻¹, which is option (c).

The idea to keep. In any medium, v = c/√(μᵣ εᵣ), and √(μᵣ εᵣ) is the refractive index. Always take the square root of the product before dividing c.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Electromagnetic Waves

Asked about 130 times in JEE Main since 2020. This question is from 2021.