JEE Main 2022 · 30 June · morning · Single correct · +4 / −1
An expression for oscillating electric field in a plane electromagnetic wave is given as E z = 300 sin(5π × 10³x - 3π × 10¹¹t) Vm⁻¹
Then, the value of magnetic field amplitude will be :
(Given : speed of light in Vacuum c = 3 × 10⁸ ms⁻¹)
- (a) 1 × 10⁻⁶ T
- (b) 5 × 10⁻⁶ T
- (c) 18 × 10⁹ T
- (d) 21 × 10⁹ T
Answer and solution
Answer (b) 5 × 10⁻⁶ T
No written solution for this question yet.