JEE Main 2025 · 7 April · evening · Single correct · +4 / −1
The unit of √(2I/(ε₀ c)) is :
(I = intensity of an electromagnetic wave, c = speed of light)
- (a) Vm
- (b) NC⁻¹
- (c) NC
- (d) Nm
Answer and solution
Answer (b) NC⁻¹
Solution
Physics sir · 4 steps
Recognise the expression: it is just the intensity formula solved for the peak electric field.
- Intensity formula. The average energy carried per unit area per unit time by an EM wave is related to its peak electric field E₀ by the relation below.
I = 1/2ε₀ c E₀² ⇒ E₀ = √(2I/(ε₀ c))
- Unit of the field. So the given expression is an electric field. Electric field is force per unit charge, so its unit is N C⁻¹, which is the same as V m⁻¹.
- Quick check. I is in W m⁻², ε₀ in C² N⁻¹ m⁻² and c in m s⁻¹. Then 2I/(ε₀ c) has unit (N m s⁻¹ m⁻²)/(C² N⁻¹ m⁻¹ s⁻¹) = N² C⁻², whose square root is N C⁻¹.
- So. The unit is N C⁻¹, option (b).
The idea to keep. When an odd combination appears in a units question, first ask whether it is a known formula rearranged. Here I = 1/2ε₀ c E₀² turns it into an electric field at once.
Answer from the NTA final answer key. Solution by PrepWiser.