JEE Main 2025 · 23 January · morning · Single correct · +4 / −1
If π/2 ≤ x ≤ (3 π)/4, then cos ⁻¹(12/13 cos x+5/13 sin x) is equal to
- (a) x+tan ⁻¹ 5/12
- (b) x-tan ⁻¹ 4/3
- (c) x+tan ⁻¹ 4/5
- (d) x-tan ⁻¹ 5/12
Answer and solution
Answer (d) x-tan ⁻¹ 5/12
Solution
Maths sir · 4 steps
Spot 12/13 and 5/13 as cos and sin of one angle, and the bracket becomes cos(x − α).
- Name the angle. Since 12² + 5² = 13², take an angle α with cos α = 12/13 and sin α = 5/13. Then α = tan⁻¹ 5/12, which is about 0.39 rad (roughly 22.6°).
- Compound angle. The bracket becomes cos x cos α + sin x sin α, which is the expansion of cos(x - α).
cos⁻¹(12/13 cos x + 5/13 sin x) = cos⁻¹(cos(x - α))
- Check the range. cos⁻¹(cos θ) = θ only when θ lies in [0, π]. For π/2 ≤ x ≤ 3π/4, x - α runs from about 1.18 to about 1.96, well inside [0, π].
- So. The expression equals x - α = x - tan⁻¹ 5/12, which is option (d).
The idea to keep. When you see a cos x + b sin x with a² + b² = 1, write it as cos(x - α). Then check that x - α lies in [0, π] before cancelling cos⁻¹ with cos.
Answer from the NTA final answer key. Solution by PrepWiser.