JEE Main 2023 · 24 January · evening · Single correct · +4 / −1

Choose the correct representation of conductometric titration of benzoic acid vs sodium hydroxide.

  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d)
    Option (d)
Answer and solution

Answer (c)

Solution

Chemistry ma’am · 3 steps

Benzoic acid is weak, so start low, dip a little, rise slowly, then shoot up once NaOH is in excess.

  1. Weak acid start. Benzoic acid is a weak acid and ionises only slightly. So very few ions are present, and the conductance starts low, not high.
    StageWhat happensConductance
    First few dropsBenzoate ions formed push back the acid's ionisation (common ion effect), so the few free H⁺ disappeardips slightly
    Up to equivalenceUn-ionised acid turns into ions: C₆H₅COOH + NaOH → C₆H₅COO⁻ + Na⁺ + H₂Orises slowly
    After equivalenceExcess Na⁺ and highly mobile OH⁻ build uprises steeply
  2. Two slopes. Both parts of the graph go up, but the line after the end point is much steeper because OH⁻ conducts far better than benzoate. The kink between the two slopes marks the equivalence point.
  3. So. Only graph (c) shows a small initial dip, a gentle rise and then a steep rise, so (c) is the correct representation.

The idea to keep. In conductometric titrations, think about which ions are being removed and which are being added. Weak acid with strong base: low start, slow rise, then a steep rise from excess OH⁻.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 170 times in JEE Main since 2020. This question is from 2023.