JEE Main 2025 · 24 January · evening · Single correct · +4 / −1
In the given structure, number of sp and sp² hybridized carbon atoms present respectively are :
- (a) 3 and 5
- (b) 3 and 6
- (c) 4 and 5
- (d) 4 and 6
Answer and solution
Answer (a) 3 and 5
Solution
Chemistry ma’am · 4 steps
Walk along the chain and count the π bonds on each carbon: one gives sp², two give sp.
- The rule. A carbon with only single bonds is sp³. A carbon with one double bond is sp². A carbon with a triple bond, or two double bonds, is sp.
- Read the structure. From left to right the chain is CH₃-CO-CH=CH-CH₂-C≡C-CH=CH-C≡N. That is 10 carbons. The O and N are not carbons, so they do not enter the count.
Carbon(s) Bonding Hybridization CH₃ and CH₂ only single bonds sp³ (2 carbons) C=O carbon one double bond sp² (1 carbon) two CH=CH units one double bond each sp² (4 carbons) C≡C carbons triple bond sp (2 carbons) C≡N carbon triple bond sp (1 carbon) - Add them up. sp carbons: 2 + 1 = 3. sp² carbons: 1 + 4 = 5. Check: 3 + 5 + 2 = 10, which matches the total carbon count.
- So. There are 3 sp and 5 sp² carbon atoms, which is option (a).
The idea to keep. For hybridization counts, write out the chain, count carbons only, and check that your sp, sp² and sp³ totals add up to the number of carbons.
Answer from the NTA final answer key. Solution by PrepWiser.