JEE Main 2025 · 24 January · evening · Single correct · +4 / −1

In the given structure, number of sp and sp² hybridized carbon atoms present respectively are :

JEE Main PYQ figure
  1. (a) 3 and 5
  2. (b) 3 and 6
  3. (c) 4 and 5
  4. (d) 4 and 6
Answer and solution

Answer (a) 3 and 5

Solution

Chemistry ma’am · 4 steps

Walk along the chain and count the π bonds on each carbon: one gives sp², two give sp.

  1. The rule. A carbon with only single bonds is sp³. A carbon with one double bond is sp². A carbon with a triple bond, or two double bonds, is sp.
  2. Read the structure. From left to right the chain is CH₃-CO-CH=CH-CH₂-C≡C-CH=CH-C≡N. That is 10 carbons. The O and N are not carbons, so they do not enter the count.
    Carbon(s)BondingHybridization
    CH₃ and CH₂only single bondssp³ (2 carbons)
    C=O carbonone double bondsp² (1 carbon)
    two CH=CH unitsone double bond eachsp² (4 carbons)
    C≡C carbonstriple bondsp (2 carbons)
    C≡N carbontriple bondsp (1 carbon)
  3. Add them up. sp carbons: 2 + 1 = 3. sp² carbons: 1 + 4 = 5. Check: 3 + 5 + 2 = 10, which matches the total carbon count.
  4. So. There are 3 sp and 5 sp² carbon atoms, which is option (a).

The idea to keep. For hybridization counts, write out the chain, count carbons only, and check that your sp, sp² and sp³ totals add up to the number of carbons.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 180 times in JEE Main since 2020. This question is from 2025.