JEE Main 2020 · 7 January · morning · Single correct · +4 / −1

The atomic radius of Ag is closed to :

  1. (a) Au
  2. (b) Cu
  3. (c) Hg
  4. (d) Ni
Answer and solution

Answer (a) Au

Solution

Chemistry ma’am · 3 steps

Silver and gold sit in the same group, and the lanthanide contraction makes them almost the same size.

  1. Normal group trend. Going down a group, a new shell is added, so the atomic radius usually grows. That holds from Cu (period 4) to Ag (period 5).
  2. Lanthanide contraction. Between Ag and Au, the 14 lanthanides fill the 4f subshell. The 4f electrons shield the nucleus poorly, so the effective nuclear charge rises and pulls the outer shell inward. This cancels the size gain from the extra shell.
    ElementPositionAtomic radius (pm)
    AgGroup 11, period 5144
    AuGroup 11, period 6144
    CuGroup 11, period 4128
    NiGroup 10, period 4125
    HgGroup 12, period 6about 150
  3. So. The atomic radius of Ag is closest to that of Au, option (a).

The idea to keep. In the d-block, the 5d element of a group has nearly the same radius as the 4d element above it (Zr–Hf, Nb–Ta, Ag–Au). That is the lanthanide contraction at work.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 120 times in JEE Main since 2020. This question is from 2020.