JEE Main 2021 · 18 March · morning · Single correct · +4 / −1

The ionic radius of Na⁺ ions is 1.02 Aᵒ. The ionic radii (in Aᵒ) of Mg²⁺ and Al³⁺, respectively, are

  1. (a) 1.05 and 0.99
  2. (b) 0.72 and 0.54
  3. (c) 0.85 and 0.99
  4. (d) 0.68 and 0.72
Answer and solution

Answer (b) 0.72 and 0.54

Solution

Chemistry ma’am · 3 steps

All three ions carry 10 electrons, so the one with more protons pulls them in tighter.

  1. Same electron count. Na⁺, Mg²⁺ and Al³⁺ each have 10 electrons, the neon configuration. Ions with the same number of electrons are called isoelectronic.
  2. Compare nuclear charge. In an isoelectronic series the electron cloud is the same, so size depends only on how many protons pull on it. More protons give a stronger pull and a smaller ion.
    IonProtonsElectronsRadius trend
    Na⁺1110largest, 1.02 Å (given)
    Mg²⁺1210smaller than 1.02 Å
    Al³⁺1310smallest
  3. So. The order must be Na⁺ > Mg²⁺ > Al³⁺. Only (b), with 0.72 Å and 0.54 Å, fits: both values are below 1.02 Å, and the Al³⁺ value is the smaller one.

The idea to keep. For isoelectronic ions, more protons means a smaller ion. Line them up by nuclear charge, and the radii fall in exactly the reverse order.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 120 times in JEE Main since 2020. This question is from 2021.