JEE Main 2024 · 9 April · morning · Single correct · +4 / −1

Relative stability of the contributing structures is :

JEE Main PYQ figure
  1. (a) (II) > (I) > (III)
  2. (b) (III) > (II) > (I)
  3. (c) (I) > (III) > (II)
  4. (d) (I) > (II) > (III)
Answer and solution

Answer (d) (I) > (II) > (III)

Solution

Chemistry ma’am · 3 steps

Neutral beats charge-separated, and a minus charge belongs on oxygen, never a plus.

  1. Rules to apply. A neutral structure with every octet complete is the most stable. Among charge-separated structures, the better one has the negative charge on the more electronegative atom.
    StructureChargesOctetsVerdict
    (I)noneall completemost stable
    (II)- on O, + on CH₂terminal C has only 6middle: charge separated, but the minus sits on electronegative O
    (III)+ on O, - on CH₂O has only 6least stable: plus on O and minus on C are both wrong
  2. Compare II and III. Both separate charges and both leave one atom with 6 electrons. (II) puts the negative charge on oxygen, which holds it well. (III) puts the positive charge on oxygen and leaves oxygen electron-deficient, which is very unfavourable.
  3. So. The order is (I) > (II) > (III), option (d).

The idea to keep. Rank resonance structures in this order of checks: no charge separation first, then complete octets, then negative charge on the more electronegative atom.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 180 times in JEE Main since 2020. This question is from 2024.