JEE Main 2020 · 7 January · evening · Single correct · +4 / −1

Among the statements (a) - (d), the correct ones are :
(a) Decomposition of hydrogen peroxide gives dioxygen.
(b) Like hydrogen peroxide, compounds, such as KCIO₃, Pb(NO₃)₂ and NaNO₃ when heated liberate dioxygen.
(c) 2-Ethylanthraquinone is useful for the industrial preparation of hydrogen peroxide.
(d) Hydrogen peroxide is used for the manufacture of sodium perborate.

  1. (a) (a), (b), (c) and (d)
  2. (b) (a) and (c) only
  3. (c) (a), (b) and (c) only
  4. (d) (a), (c) and (d) only
Answer and solution

Answer (a) (a), (b), (c) and (d)

Solution

Chemistry ma’am · 2 steps

Test each statement on its own: all four are standard facts about H₂O₂, so every one stays in.

  1. Judge each statement. Check every statement separately against what you know about H₂O₂. Only then match the true ones to an option.
    StatementWhat actually happensVerdict
    (a) H₂O₂ decomposes to O₂2H₂O₂ → 2H₂O + O₂True
    (b) Salts that give O₂ on heating2KClO₃ →(Δ) 2KCl + 3O₂, 2Pb(NO₃)₂ →(Δ) 2PbO + 4NO₂ + O₂, 2NaNO₃ →(Δ) 2NaNO₂ + O₂True
    (c) 2-Ethylanthraquinone processAir oxidises 2-ethylanthraquinol to give H₂O₂ and 2-ethylanthraquinone. H₂ over Pd reduces the quinone back, so the cycle repeats.True
    (d) Sodium perborateH₂O₂ is used to make sodium perborate, a bleach in washing powdersTrue
  2. So. All four statements are correct, so the answer is option (a): (a), (b), (c) and (d).

The idea to keep. Judge each statement alone before you look at the options. For H₂O₂, remember: it releases O₂, it is made by the anthraquinone process, and it is used to make perborate.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Hydrogen & s-Block Elements

Asked about 130 times in JEE Main since 2020. This question is from 2020.