JEE Main 2020 · 7 January · evening · Single correct · +4 / −1
Among the statements (a) - (d), the correct ones are :
(a) Decomposition of hydrogen peroxide gives dioxygen.
(b) Like hydrogen peroxide, compounds, such as KCIO₃, Pb(NO₃)₂ and NaNO₃ when heated liberate dioxygen.
(c) 2-Ethylanthraquinone is useful for the industrial preparation of hydrogen peroxide.
(d) Hydrogen peroxide is used for the manufacture of sodium perborate.
- (a) (a), (b), (c) and (d)
- (b) (a) and (c) only
- (c) (a), (b) and (c) only
- (d) (a), (c) and (d) only
Answer and solution
Answer (a) (a), (b), (c) and (d)
Solution
Chemistry ma’am · 2 steps
Test each statement on its own: all four are standard facts about H₂O₂, so every one stays in.
- Judge each statement. Check every statement separately against what you know about H₂O₂. Only then match the true ones to an option.
Statement What actually happens Verdict (a) H₂O₂ decomposes to O₂ 2H₂O₂ → 2H₂O + O₂ True (b) Salts that give O₂ on heating 2KClO₃ →(Δ) 2KCl + 3O₂, 2Pb(NO₃)₂ →(Δ) 2PbO + 4NO₂ + O₂, 2NaNO₃ →(Δ) 2NaNO₂ + O₂ True (c) 2-Ethylanthraquinone process Air oxidises 2-ethylanthraquinol to give H₂O₂ and 2-ethylanthraquinone. H₂ over Pd reduces the quinone back, so the cycle repeats. True (d) Sodium perborate H₂O₂ is used to make sodium perborate, a bleach in washing powders True - So. All four statements are correct, so the answer is option (a): (a), (b), (c) and (d).
The idea to keep. Judge each statement alone before you look at the options. For H₂O₂, remember: it releases O₂, it is made by the anthraquinone process, and it is used to make perborate.
Answer from the NTA final answer key. Solution by PrepWiser.