JEE Main 2021 · 27 August · evening · Single correct · +4 / −1

The oxide that gives H₂O₂ most readily on treatment with H₂O is :

  1. (a) PbO₂
  2. (b) Na₂O₂
  3. (c) SnO₂
  4. (d) BaO₂ . 8H₂O
Answer and solution

Answer (b) Na₂O₂

Solution

Chemistry ma’am · 2 steps

First check which oxides are true peroxides, then ask which one water alone can break apart.

  1. Need a peroxide. H₂O₂ forms only when the solid already contains the peroxide ion O₂²⁻ (an O-O bond). Hydrolysis just adds H⁺ to that ion.
    OxideMetal oxidation stateHas O₂²⁻?With water
    PbO₂+4No, it has two O²⁻no H₂O₂
    Na₂O₂+1Yeshydrolysed by cold water to give H₂O₂
    SnO₂+4No, it has two O²⁻no H₂O₂
    BaO₂.8H₂O+2Yessparingly soluble, so it needs dilute H₂SO₄

    Na₂O₂ + 2H₂O →(ice-cold) 2NaOH + H₂O₂

  2. So. Na₂O₂, option (b), gives H₂O₂ most readily on treatment with water.

The idea to keep. To get H₂O₂, the oxide must already hold an O-O bond, so check the oxidation state first. Na₂O₂ hydrolyses in cold water, but BaO₂ needs an acid.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Hydrogen & s-Block Elements

Asked about 130 times in JEE Main since 2020. This question is from 2021.