JEE Main 2024 · 5 April · evening · Single correct · +4 / −1

The number of moles of methane required to produce 11 g CO₂(g) after complete combustion is : (Given molar mass of methane in g mol⁻¹: 16 )

  1. (a) 0.35
  2. (b) 0.25
  3. (c) 0.5
  4. (d) 0.75
Answer and solution

Answer (b) 0.25

Solution

Chemistry ma’am · 4 steps

Each CH₄ gives exactly one CO₂, so find moles of CO₂ and you have moles of methane.

  1. Balanced equation. Methane burns completely to carbon dioxide and water.

    CH₄ + 2O₂ → CO₂ + 2H₂O

  2. Moles of CO2. Molar mass of CO₂ is 12 + 2 × 16 = 44 g mol⁻¹. So 11 g is 11/44 = 0.25 mol.
  3. Use the ratio. The equation has a 1 : 1 ratio between CH₄ and CO₂, because methane has one carbon atom and each carbon ends up in one CO₂.
  4. So. Moles of methane needed = 0.25 mol, which is option (b).

The idea to keep. In combustion questions, follow the carbon atoms: moles of CO₂ formed equal moles of C in the fuel. Convert the given mass to moles first, then use the mole ratio.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Mole Concept & Stoichiometry

Asked about 210 times in JEE Main since 2020. This question is from 2024.