JEE Main 2020 · 3 September · evening · Single correct · +4 / −1
For the reaction
2A + 3B + 3/2C → 3P, which statement is correct ?
- (a) dn_A/dt = dn_B/dt = dn_C/dt
- (b) dn_A/dt = 2/3dn_B/dt = 3/4dn_C/dt
- (c) dn_A/dt = 3/2dn_B/dt = 3/4dn_C/dt
- (d) dn_A/dt = 2/3dn_B/dt = 4/3dn_C/dt
Answer and solution
Answer (d) dn_A/dt = 2/3dn_B/dt = 4/3dn_C/dt
Solution
Chemistry ma’am · 3 steps
Divide each rate by its own coefficient, set them equal, then solve for dn_A/dt.
- One common rate. Each species is used up at a rate set by its coefficient. Dividing each dn/dt by its coefficient gives the same number for all of them. A, B and C are all reactants, so all three derivatives carry the same negative sign.
-1/2dn_A/dt = -1/3dn_B/dt = -1/(3/2)dn_C/dt = -2/3dn_C/dt
- Isolate the A rate. Multiply every term by -2 so that dn_A/dt stands alone. The B term becomes 2/3dn_B/dt. The C term becomes 2 × 2/3 = 4/3, giving 4/3dn_C/dt.
- So. dn_A/dt = 2/3dn_B/dt = 4/3dn_C/dt, which is option (d).
The idea to keep. Write the common rate as 1/νdn/dt for every species, then rearrange. With a fractional coefficient like 3/2, dividing by it means multiplying by 2/3.
Answer from the NTA final answer key. Solution by PrepWiser.