JEE Main 2020 · 3 September · morning · Single correct · +4 / −1

The atomic number of the element unnilennium is :

  1. (a) 109
  2. (b) 102
  3. (c) 119
  4. (d) 108
Answer and solution

Answer (a) 109

Solution

Chemistry ma’am · 2 steps

Break the name into its digit roots, read them left to right, and the number writes itself.

  1. IUPAC digit roots. Each digit has a root: 0 nil, 1 un, 2 bi, 3 tri, 4 quad, 5 pent, 6 hex, 7 sept, 8 oct, 9 enn. The roots are joined in the order of the digits, and the name ends in "ium".
    Part of the nameDigit
    un1
    nil0
    enn9
    iumending, no digit
  2. So. Un-nil-enn-ium reads as 1, 0, 9, so the atomic number is 109, option (a). Today this element is named meitnerium, Mt.

The idea to keep. For any temporary IUPAC name, split it into digit roots and read them in order. "nil" is 0 and "enn" is 9, and those two are the ones students mix up most.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 120 times in JEE Main since 2020. This question is from 2020.