JEE Main 2023 · 11 April · evening · Single correct · +4 / −1

The Thermodynamic process, in which internal energy of the system remains constant is

  1. (a) Isobaric
  2. (b) Isochoric
  3. (c) Adiabatic
  4. (d) Isothermal
Answer and solution

Answer (d) Isothermal

Solution

Physics sir · 2 steps

For an ideal gas, internal energy depends only on temperature, so fix T and you have fixed U.

  1. U depends on T. For an ideal gas, internal energy is U = nCᵥT. With a fixed amount of gas, U changes only when the temperature changes.

    Δ U = nCᵥ Δ T

    ProcessWhat is held constantΔ TΔ U
    IsobaricPressurenot zero in generalnot zero
    IsochoricVolumenot zero in generalnot zero
    AdiabaticHeat exchange, Q = 0not zeroΔ U = -W, not zero
    IsothermalTemperaturezerozero
  2. So. Only the isothermal process keeps T constant, so Δ U = 0 and internal energy stays the same. The answer is (d).

The idea to keep. Whenever a question asks about Δ U for an ideal gas, look at the temperature. Same T means same U, whatever happens to P and V.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Thermodynamics

Asked about 150 times in JEE Main since 2020. This question is from 2023.