JEE Main 2025 · 8 April · evening · Single correct · +4 / −1

A monoatomic gas having γ = 5/3 is stored in a thermally insulated container and the gas is suddenly compressed to ( 1/8 )ᵗʰ of its initial volume. The ratio of final pressure and initial pressure is:
(γ is the ratio of specific heats of the gas at constant pressure and at constant volume)

  1. (a) 16
  2. (b) 32
  3. (c) 28
  4. (d) 40
Answer and solution

Answer (b) 32

Solution

Physics sir · 3 steps

Insulated and sudden means no heat flows, so this is adiabatic: use PV^γ constant, not Boyle's law.

  1. Spot the process. The container is thermally insulated and the compression is sudden, so no heat enters or leaves the gas. That makes the process adiabatic.

    P₁ V₁^γ = P₂ V₂^γ ⇒ P₂/P₁ = (V₁/V₂)^γ

  2. Put in numbers. The volume becomes 1/8 of its initial value, so V₁/V₂ = 8 = 2³. Then P₂/P₁ = (2³)^(5/3) = 2⁵ = 32.
  3. So. The final pressure is 32 times the initial pressure, which is option (b).

The idea to keep. Read the setup words: insulated or sudden means adiabatic, so PV^γ stays constant. Write the volume ratio as a power of 2 and the fractional power of γ becomes easy.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Thermodynamics

Asked about 150 times in JEE Main since 2020. This question is from 2025.