JEE Main 2024 · 5 April · evening · Single correct · +4 / −1

During an adiabatic process, if the pressure of a gas is found to be proportional to the cube of its absolute temperature, then the ratio of C_P/C_V for the gas is :

  1. (a) 5/3
  2. (b) 3/2
  3. (c) 7/5
  4. (d) 9/7
Answer and solution

Answer (b) 3/2

Solution

Physics sir · 3 steps

Rewrite the adiabatic law in terms of P and T, then match the power of T to 3.

  1. Remove the volume. For an adiabatic process PV^γ = constant. From the ideal gas law, V ∝ T/P. Substituting gives P (T/P)^γ = constant, which is P^(1-γ)T^γ = constant.

    P ∝ T^(γ/(γ - 1))

  2. Match the exponent. The question says P ∝ T³, so γ/(γ - 1) = 3. This gives γ = 3γ - 3, so 2γ = 3.
  3. So. γ = C_P/C_V = 3/2, which is option (b).

The idea to keep. In an adiabatic process, P ∝ T^(γ/(γ-1)). Derive it from PV^γ and PV = nRT instead of memorising it, and then equate the powers.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Thermodynamics

Asked about 150 times in JEE Main since 2020. This question is from 2024.