JEE Main 2024 · 5 April · evening · Single correct · +4 / −1
During an adiabatic process, if the pressure of a gas is found to be proportional to the cube of its absolute temperature, then the ratio of C_P/C_V for the gas is :
- (a) 5/3
- (b) 3/2
- (c) 7/5
- (d) 9/7
Answer and solution
Answer (b) 3/2
Solution
Physics sir · 3 steps
Rewrite the adiabatic law in terms of P and T, then match the power of T to 3.
- Remove the volume. For an adiabatic process PV^γ = constant. From the ideal gas law, V ∝ T/P. Substituting gives P (T/P)^γ = constant, which is P^(1-γ)T^γ = constant.
P ∝ T^(γ/(γ - 1))
- Match the exponent. The question says P ∝ T³, so γ/(γ - 1) = 3. This gives γ = 3γ - 3, so 2γ = 3.
- So. γ = C_P/C_V = 3/2, which is option (b).
The idea to keep. In an adiabatic process, P ∝ T^(γ/(γ-1)). Derive it from PV^γ and PV = nRT instead of memorising it, and then equate the powers.
Answer from the NTA final answer key. Solution by PrepWiser.