JEE Main 2025 · 4 Apr · Shift 1 · Classical Probability The probability, of forming a 12 persons committee from 4 engineers, 2 doctors and 10 professors containing at least 3 engineers and at least 1 doctor, is (A) 129182\frac{129}{182}182129 (B) 1726\frac{17}{26}2617 (C) 1926\frac{19}{26}2619 (D) 103182\frac{103}{182}182103 Answer: (A) Step-by-step solution
JEE Main 2024 · 1 Feb · Shift 2 · Addition Theorem Let Ajay will not appear in JEE exam with probability p=27\mathrm{p}=\frac{2}{7}p=72 , while both Ajay and Vijay will appear in the exam with probability q=15\mathrm{q}=\frac{1}{5}q=51 . Then the probability, that Ajay will appear in the exam and Vijay will not appear is : (A)935\frac{9}{35}359 (B)335\frac{3}{35}353 (C)2435\frac{24}{35}3524 (D)1835\frac{18}{35}3518 Answer: (D) Step-by-step solution
JEE Main 2023 · 1 Feb · Shift 2 · Sample Space and Events Two dice are thrown independently. Let A\mathrm{A}A be the event that the number appeared on the 1st 1^{\text {st }}1st die is less than the number appeared on the 2nd 2^{\text {nd }}2nd die, B\mathrm{B}B be the event that the number appeared on the 1st 1^{\text {st }}1st die is even and that on the second die is odd, and C\mathrm{C}C be the event that the number appeared on the 1st 1^{\text {st }}1st die is odd and that on the 2nd 2^{\text {nd }}2nd is even. Then : (A)A and B are mutually exclusive(B)the number of favourable cases of the events A, B and C are 15, 6 and 6 respectively(C)B and C are independent(D)the number of favourable cases of the event (A∪B)∩C(\mathrm{A\cup B)\cap C}(A∪B)∩C is 6 Answer: (D) Step-by-step solution
JEE Main 2022 · 26 Jul · Shift 1 · Mutually Exclusive Events Let E1,E2,E3\mathrm{E}_{1}, \mathrm{E}_{2}, \mathrm{E}_{3}E1 ,E2 ,E3 be three mutually exclusive events such that P(E1)=2+3p6,P(E2)=2−p8\mathrm{P}\left(\mathrm{E}_{1}\right)=\frac{2+3 \mathrm{p}}{6}, \mathrm{P}\left(\mathrm{E}_{2}\right)=\frac{2-\mathrm{p}}{8}P(E1 )=62+3p ,P(E2 )=82−p and P(E3)=1−p2\mathrm{P}\left(\mathrm{E}_{3}\right)=\frac{1-\mathrm{p}}{2}P(E3 )=21−p . If the maximum and minimum values of p\mathrm{p}p are p1\mathrm{p}_{1}p1 and p2\mathrm{p}_{2}p2 , then (p1+p2)\left(\mathrm{p}_{1}+\mathrm{p}_{2}\right)(p1 +p2 ) is equal to : (A)23\frac{2}{3}32 (B)53\frac{5}{3}35 (C)54\frac{5}{4}45 (D)1 Answer: (B) Step-by-step solution