JEE Main 2024 · 6 April · evening · Single correct · +4 / −1

Energy of 10 non rigid diatomic molecules at temperature T is :

  1. (a) 35 RT
  2. (b) 7/2 RT
  3. (c) 70 K B T
  4. (d) 35 K B T
Answer and solution

Answer (d) 35 K B T

Solution

Physics sir · 2 steps

Count every quadratic energy term, give each one 1/2k_BT, then multiply by 10 molecules.

  1. Count energy terms. A non-rigid diatomic molecule moves in 3 directions and rotates about 2 axes. It also vibrates, and vibration carries two terms: kinetic energy and potential energy of the stretched bond.
    MotionQuadratic termsEnergy per molecule
    Translation33/2k_BT
    Rotation2k_BT
    Vibration (KE + PE)2k_BT
    Total77/2k_BT

    E = 10 × 7/2k_BT = 35 k_BT

  2. So. The question counts molecules, not moles, so the constant is k_B, not R. The energy of 10 molecules is 35 k_BT, option (d).

The idea to keep. Each quadratic energy term gets 1/2k_BT per molecule, and a vibration mode always brings two terms. Use k_B when you count molecules and R when you count moles.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Kinetic Theory of Gases

Asked about 130 times in JEE Main since 2020. This question is from 2024.