JEE Main 2024 · 6 April · evening · Single correct · +4 / −1
Energy of 10 non rigid diatomic molecules at temperature T is :
- (a) 35 RT
- (b) 7/2 RT
- (c) 70 K B T
- (d) 35 K B T
Answer and solution
Answer (d) 35 K B T
Solution
Physics sir · 2 steps
Count every quadratic energy term, give each one 1/2k_BT, then multiply by 10 molecules.
- Count energy terms. A non-rigid diatomic molecule moves in 3 directions and rotates about 2 axes. It also vibrates, and vibration carries two terms: kinetic energy and potential energy of the stretched bond.
Motion Quadratic terms Energy per molecule Translation 3 3/2k_BT Rotation 2 k_BT Vibration (KE + PE) 2 k_BT Total 7 7/2k_BT E = 10 × 7/2k_BT = 35 k_BT
- So. The question counts molecules, not moles, so the constant is k_B, not R. The energy of 10 molecules is 35 k_BT, option (d).
The idea to keep. Each quadratic energy term gets 1/2k_BT per molecule, and a vibration mode always brings two terms. Use k_B when you count molecules and R when you count moles.
Answer from the NTA final answer key. Solution by PrepWiser.