JEE Main 2020 · 3 September · morning · Single correct · +4 / −1

Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature T is :

JEE Main PYQ figure
  1. (a) 3/2RT
  2. (b) 9/2RT
  3. (c) 5/2RT
  4. (d) 3RT
Answer and solution

Answer (d) 3RT

Solution

Physics sir · 3 steps

A rigid triangle is a nonlinear molecule: 3 ways to move plus 3 ways to spin, so 6 degrees of freedom.

  1. Translation. The centre of mass can move along x, y and z. That gives 3 translational degrees of freedom.
  2. Rotation. The three atoms do not lie on one line, so the molecule has a real moment of inertia about all three axes. That gives 3 rotational degrees of freedom. The rods are rigid, so there is no vibration to count.

    U = f × 1/2RT = 6 × 1/2RT = 3RT

  3. So. By equipartition each degree of freedom carries 1/2RT per mole. With f = 6, the internal energy is 3RT, option (d).

The idea to keep. Count degrees of freedom by shape: monatomic 3, linear rigid 5, nonlinear rigid 6. Multiply by 1/2RT per mole to get the internal energy.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Kinetic Theory of Gases

Asked about 130 times in JEE Main since 2020. This question is from 2020.