JEE Main 2024 · 31 January · evening · Single correct · +4 / −1
A gas mixture consists of 8 moles of argon and 6 moles of oxygen at temperature T. Neglecting all vibrational modes, the total internal energy of the system is:
- (a) 29 RT
- (b) 27 RT
- (c) 20 RT
- (d) 21 RT
Answer and solution
Answer (b) 27 RT
Solution
Physics sir · 3 steps
Give each gas its own degrees of freedom, find each energy, and add them up.
- Equipartition. Each degree of freedom carries 1/2RT per mole. So n moles of a gas with f degrees of freedom have U = f/2nRT.
- Count freedoms. Argon is monatomic, so it has only 3 translational degrees of freedom. Oxygen is diatomic: 3 translational plus 2 rotational gives f = 5, because vibration is neglected.
U = 8 × 3/2RT + 6 × 5/2RT = 12 RT + 15 RT
- So. The total internal energy is U = 27 RT, which is option (b).
The idea to keep. For a mixture, internal energy just adds up gas by gas. Monatomic gets f = 3, diatomic without vibration gets f = 5, and each mole holds f/2RT.
Answer from the NTA final answer key. Solution by PrepWiser.