JEE Main 2025 · 7 April · morning · Single correct · +4 / −1
Match the List I with List II
Choose the correct answer from the options given below:
| List - I | List - II | ||
|---|---|---|---|
| (A) | Triatomic rigid gas | (I) | Cₚ/Cᵥ=5/3 |
| (B) | Diatomic non-rigid gas | (II) | Cₚ/Cᵥ=7/5 |
| (C) | Monoatomic gas | (III) | Cₚ/Cᵥ=4/3 |
| (D) | Diatomic rigid gas | (IV) | Cₚ/Cᵥ=9/7 |
- (a) A-III, B-IV, C-I, D-II
- (b) A-II, B-IV, C-I, D-III
- (c) A-IV, B-II, C-III, D-I
- (d) A-III, B-II, C-IV, D-I
Answer and solution
Answer (a) A-III, B-IV, C-I, D-II
Solution
Physics sir · 3 steps
Count the degrees of freedom f for each gas, then γ = 1 + 2/f matches it in one line.
- The one formula. By equipartition, Cᵥ = f/2R and Cₚ = Cᵥ + R. Dividing gives γ = Cₚ/Cᵥ = 1 + 2/f, so you only need f for each gas.
- Counting f. Every molecule has 3 translational modes. A diatomic molecule adds 2 rotational modes, and a rigid non-linear triatomic molecule adds 3. If the molecule is non-rigid, each vibrational mode adds 2, one for kinetic energy and one for potential energy.
Gas Degrees of freedom f γ = 1 + 2/f Match (A) Triatomic rigid 3 + 3 = 6 4/3 III (B) Diatomic non-rigid 3 + 2 + 2 = 7 9/7 IV (C) Monoatomic 3 5/3 I (D) Diatomic rigid 3 + 2 = 5 7/5 II - So. The matching is A-III, B-IV, C-I, D-II, which is option (a).
The idea to keep. For any ideal gas, γ = 1 + 2/f. Get f right: 3 for translation, 2 or 3 for rotation, and 2 for each vibrational mode.
Answer from the NTA final answer key. Solution by PrepWiser.