JEE Main 2024 · 4 April · evening · Single correct · +4 / −1

The translational degrees of freedom (fₜ) and rotational degrees of freedom (fᵣ) of CH₄ molecule are:

  1. (a) fₜ=2 and fᵣ=2
  2. (b) fₜ=3 and fᵣ=3
  3. (c) fₜ=3 and 4fᵣ=2
  4. (d) fₜ=2 and fᵣ=3
Answer and solution

Answer (b) fₜ=3 and fᵣ=3

Solution

Physics sir · 4 steps

Methane is a 3D tetrahedron, not a line, so it can spin about all three axes.

  1. Translation. Every molecule, whatever its shape, can move its centre of mass along x, y and z. So fₜ = 3 for any gas molecule.
  2. Shape of methane. In CH₄ the carbon sits at the centre of a tetrahedron with four H atoms at the corners. The atoms do not lie on one line.
  3. Rotation. A linear molecule has only 2 rotational degrees of freedom, because rotation about its own axis does not count. A non-linear molecule like CH₄ has a real moment of inertia about all three axes, so fᵣ = 3.
  4. So. fₜ = 3 and fᵣ = 3, which is option (b).

The idea to keep. Translation is always 3. Rotation is 2 for a linear molecule and 3 for a non-linear one, so check the shape before you count.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Kinetic Theory of Gases

Asked about 130 times in JEE Main since 2020. This question is from 2024.