JEE Main 2025 · 22 January · evening · Single correct · +4 / −1

For a diatomic gas, if γ₁=((C p)/(C v)) for rigid molecules and γ₂=((C p)/(C v)) for another diatomic molecules, but also having vibrational modes. Then, which one of the following options is correct? (Cp and Cv are specific heats of the gas at constant pressure and volume)

  1. (a) γ₂<γ₁
  2. (b) γ₂>γ₁
  3. (c) γ₂=γ₁
  4. (d) 2 γ₂=γ₁
Answer and solution

Answer (a) γ₂<γ₁

Solution

Physics sir · 2 steps

Vibration adds degrees of freedom, and every extra degree of freedom pulls γ down towards 1.

  1. Gamma from f. By equipartition, each degree of freedom gives 1/2R to Cᵥ, so Cᵥ = f/2R and Cₚ = Cᵥ + R. Dividing the two gives the formula below.

    γ = Cₚ/Cᵥ = 1 + 2/f

    MoleculeDegrees of freedom fγ = 1 + 2/f
    Rigid diatomic3 translational + 2 rotational = 5γ₁ = 7/5 = 1.4
    Diatomic with vibration5 + 2 vibrational (kinetic + potential) = 7γ₂ = 9/7 ≈ 1.29
  2. So. A larger f makes 2/f smaller, so γ₂ = 1.29 is less than γ₁ = 1.4. The answer is (a), γ₂ < γ₁.

The idea to keep. Remember γ = 1 + 2/f. The more ways a molecule can store energy, the larger f is and the closer γ gets to 1. One vibrational mode adds 2 to f.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Kinetic Theory of Gases

Asked about 130 times in JEE Main since 2020. This question is from 2025.