JEE Main 2020 · 6 September · morning · Single correct · +4 / −1

Identify the correct output signal Y in the given combination of gates (as shown) for the given inputs A and B.

JEE Main PYQ figure
  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d)
    Option (d)
Answer and solution

Answer (d)

Solution

Physics sir · 3 steps

Two NOT gates feeding a NAND is just an OR gate in disguise, so Y is low only when A and B are both low.

  1. Reduce the circuit. The NAND gate receives Ā and B̄, so Y = Ā·B̄̅. De Morgan's theorem turns this into a plain OR.

    Y = Ā·B̄̅ = Ā̄̄ + B̄̄̄ = A + B

  2. Read the waveforms. Split the time axis wherever A or B changes. Then mark Y as 0 only in the intervals where both inputs are 0.
    Time intervalABY = A + B
    0 to 7.50, then 1 after 511
    7.5 to 10000
    10 to 150, then 1 after 12.511
    15 to about 17000
    about 17 onwards1, then 0 after about 190, then 1 after about 191
  3. So. Y is high everywhere except two short gaps, from 7.5 to 10 and from 15 to about 17. Only option (d) has this shape.

The idea to keep. Bubbles on the inputs of a NAND turn it into an OR, and bubbles on the inputs of a NOR turn it into an AND. Simplify the gate first, then read the waveforms interval by interval.

Answer from the NTA final answer key. Solution by PrepWiser.

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Asked about 170 times in JEE Main since 2020. This question is from 2020.