JEE Main 2022 · 27 June · morning · Single correct · +4 / −1

Identify the correct Logic Gate for the following output (Y) of two inputs A and B.

JEE Main PYQ figure
  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d)
    Option (d)
Answer and solution

Answer (b)

Solution

Physics sir · 3 steps

Read the waveforms slot by slot into a truth table, then see which circuit gives the same column of Y.

  1. Read the slots. The dashed lines cut the graph into time slots, and in each slot you note A, B and Y. Over the slots you see AB = 11, 00, 01, 10, 11, 00, 01, 10 with Y = 0, 1, 1, 1, 0, 1, 1, 1.
  2. Truth table. So Y = 1 for AB = 00, 01, 10 and Y = 0 only for AB = 11. The output goes low only when both inputs are high, and that is a NAND gate, Y = A · B̅.
    SourceOutput expressionY for AB = 00, 01, 10, 11Matches?
    Graphread off1, 1, 1, 0target
    (a) OR then NOTA + B̅1, 0, 0, 0no
    (b) AND then NOTA · B̅1, 1, 1, 0yes
    (c) OR with inverted A, then NOTĀ + B̅ = AB̄0, 0, 1, 0no
    (d) NAND with inverted BA · B̄̅ = Ā + B1, 1, 0, 1no
  3. So. Only the AND gate followed by a NOT gate, which together make a NAND gate, reproduces the waveform. The answer is (b).

The idea to keep. For waveform questions, turn the graph into a truth table first. One output that differs from the rest, like a single 0 at AB = 11, names the gate straight away: here it is NAND.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Semiconductors & Electronic Devices

Asked about 170 times in JEE Main since 2020. This question is from 2022.