JEE Main 2023 · 29 January · evening · Single correct · +4 / −1
For the given logic gates combination, the correct truth table will be
- (a)
- (b)
- (c)
- (d)
Answer and solution
Answer (d)
Solution
Physics sir · 2 steps
Follow each crossing wire to its AND gate, and you will see X is high only when A and B differ.
- Trace the wires. The two wires cross without joining. The top AND gate gets Ā and B, and the bottom AND gate gets A and B̄.
X = Ā B + A B̄
A and B ĀB (top) AB̄ (bottom) X (OR) 0 and 0 0 0 0 0 and 1 1 0 1 1 and 0 0 1 1 1 and 1 0 0 0 - So. The output column reads 0, 1, 1, 0. This is the XOR gate, which matches option (d).
The idea to keep. For a gate combination, write the Boolean expression at each gate output first, then fill the truth table row by row. ĀB + AB̄ is XOR, so learn to spot it on sight.
Answer from the NTA final answer key. Solution by PrepWiser.