JEE Main 2023 · 29 January · evening · Single correct · +4 / −1

For the given logic gates combination, the correct truth table will be

JEE Main PYQ figure
  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d)
    Option (d)
Answer and solution

Answer (d)

Solution

Physics sir · 2 steps

Follow each crossing wire to its AND gate, and you will see X is high only when A and B differ.

  1. Trace the wires. The two wires cross without joining. The top AND gate gets Ā and B, and the bottom AND gate gets A and B̄.

    X = Ā B + A B̄

    A and BĀB (top)AB̄ (bottom)X (OR)
    0 and 0000
    0 and 1101
    1 and 0011
    1 and 1000
  2. So. The output column reads 0, 1, 1, 0. This is the XOR gate, which matches option (d).

The idea to keep. For a gate combination, write the Boolean expression at each gate output first, then fill the truth table row by row. ĀB + AB̄ is XOR, so learn to spot it on sight.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Semiconductors & Electronic Devices

Asked about 170 times in JEE Main since 2020. This question is from 2023.