JEE Main 2023 · 8 April · morning · Single correct · +4 / −1

For the logic circuit shown, the output waveform at Y is:

JEE Main PYQ figure
  1. (a)
    Option (a)
  2. (b)
    Option (b)
  3. (c)
    Option (c)
  4. (d)
    Option (d)
Answer and solution

Answer (b)

Solution

Physics sir · 3 steps

Each NAND with its inputs joined is just a NOT gate, so the whole circuit turns into a plain OR gate.

  1. Shorted NAND. When both inputs of a NAND gate are tied together, the output is A · A̅ = A̅. So the first two gates give A̅ and B̅.

    Y = A̅·B̅̅ = A̅̅̅ + B̅̅̅ = A + B

  2. Read the inputs. By De Morgan's theorem the circuit is an OR gate. A is 0 up to t = 2 and 1 after that. B is 1 only from 1 to 2 and after 3.
    IntervalABY = A + B
    0 to 1000
    1 to 2011
    2 to 3101
    3 to 4111
  3. So. Y stays low from 0 to 1 and is high from t = 1 onwards. That is waveform (b).

The idea to keep. NAND gates with joined inputs act as NOT gates. Inverting both inputs of a NAND gives an OR gate, so reduce the circuit first and then read the waveform interval by interval.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Semiconductors & Electronic Devices

Asked about 170 times in JEE Main since 2020. This question is from 2023.