JEE Main 2024 · 9 April · evening · Single correct · +4 / −1

In the truth table of the above circuit the value of X and Y are :

JEE Main PYQ figure
  1. (a) 1, 1
  2. (b) 0, 1
  3. (c) 1, 0
  4. (d) 0, 0
Answer and solution

Answer (a) 1, 1

Solution

Physics sir · 3 steps

Both AND outputs are 0 when A and B differ, and a NOR of two zeros gives 1.

  1. Read the gates. The top AND gate gives AB. The bottom AND gate gets both inputs inverted, so it gives ĀB̄. Both feed a NOR gate, because the output has a bubble.

    E = AB + ĀB̄̅

    A, BABĀB̄E (NOR)
    0, 0010
    0, 1001 (X)
    1, 0001 (Y)
    1, 1100
  2. Check. The rows for 0, 0 and 1, 1 give 0, matching the given table. The circuit is an XOR gate, which outputs 1 only when the inputs differ.
  3. So. X = 1 and Y = 1, which is option (a).

The idea to keep. Write the Boolean expression gate by gate, then fill a truth table. AB and ĀB̄ fed into a NOR makes an XOR gate, so the output is 1 only when the inputs differ.

Answer from the NTA final answer key. Solution by PrepWiser.

Study Semiconductors & Electronic Devices

Asked about 170 times in JEE Main since 2020. This question is from 2024.