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Solid State JEE Main PYQs, 2020 to 2024

Solid State has 42 questions in JEE Main papers from 2020 to 2024, about 8.4 per year across all shifts. The most asked topic is Crystal Systems and Unit Cells (19 questions), followed by Voids (9) and Crystal Defects (6).

Updated

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42Total PYQs
5Years covered
5Topics
2024 Apr S1Latest paper

Solid State questions per year

YearQuestions
20241
202312
20229
202115
20205

Topic-wise weightage

TopicQuestionsShare of chapterLast asked
Crystal Systems and Unit Cells1945%2023
Voids922%2023
Crystal Defects614%2023
Crystalline and Amorphous Solids614%2024
Close Packing25%2023

Sample questions from recent papers

JEE Main 2024 · 6 Apr · Shift 1 · Crystalline and Amorphous Solids

Which of the following material is not a semiconductor.

  1. (A)Copper oxide
  2. (B)Graphite
  3. (C)Silicon
  4. (D)Germanium

Answer: (B)

Step-by-step solution

JEE Main 2023 · 15 Apr · Shift 1 · Crystal Systems and Unit Cells

Which of the following expressions is correct in case of a CsCl\mathrm{CsCl} unit cell (edge length 'a')?
  1. (A)rCs++rCl−=32a\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{\sqrt{3}}{2} \mathrm{a}
  2. (B)rCs++rCl−=a2\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{\mathrm{a}}{\sqrt{2}}
  3. (C)rCs++rCl−=a\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\mathrm{a}
  4. (D)rCs++rCl−=a2\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{\mathrm{a}}{2}

Answer: (A)

Step-by-step solution

JEE Main 2023 · 10 Apr · Shift 2 · Close Packing

The correct relationships between unit cell edge length 'aa' and radius of sphere 'rr' for face-centred and body-centred cubic structures respectively are :

  1. (A)r=22ar=2 \sqrt{2} a and 3r=4a\sqrt{3} r=4 a
  2. (B)r=22ar=2 \sqrt{2} a and 4r=3a4 r=\sqrt{3} a
  3. (C)22r=a2 \sqrt{2} r=a and 3r=4a\sqrt{3} r=4 a
  4. (D)22r=a2 \sqrt{2} r=a and 4r=3a4 r=\sqrt{3} a

Answer: (D)

Step-by-step solution

JEE Main 2023 · 6 Apr · Shift 1 · Voids

A compound is formed by two elements X\mathrm{X} and Y\mathrm{Y}. The element Y\mathrm{Y} forms cubic close packed arrangement and those of element X\mathrm{X} occupy one third of the tetrahedral voids. What is the formula of the compound?

  1. (A)XY3\mathrm{XY}_{3}
  2. (B)X3Y2\mathrm{X_3Y}_{2}
  3. (C)X3Y\mathrm{X_3Y}
  4. (D)X2Y3\mathrm{X_2Y}_{3}

Answer: (D)

Step-by-step solution

JEE Main 2023 · 24 Jan · Shift 1 · Crystal Defects

When Fe0.93O\mathrm{Fe_{0.93}O} is heated in presence of oxygen, it converts to Fe2O3\mathrm{Fe_2O_3}. The number of correct statement/s from the following is ________

A. The equivalent weight of Fe0.93O\mathrm{Fe_{0.93}O} is Molecular weight0.79{{\mathrm{Molecular\,weight}} \over {0.79}}

B. The number of moles of Fe2+^{2+} and Fe3+^{3+} in 1 mole of Fe0.93O\mathrm{Fe_{0.93}O} is 0.79 and 0.14 respectively

C. Fe0.93O\mathrm{Fe_{0.93}O} is metal deficient with lattice comprising of cubic closed packed arrangement of O2−^{2-} ions

D. The % composition of Fe2+^{2+} and Fe3+^{3+} in Fe0.93O\mathrm{Fe_{0.93}O} is 85% and 15% respectively

Answer: 4

Step-by-step solution

All 42 questions are in the free PDF above, grouped by topic.

Frequently asked

How many questions come from Solid State in JEE Main?

42 questions from 2020 to 2024, about 8.4 per year. In 2024 it had 1.

Which Solid State topics are most important for JEE Main?

By past papers: Crystal Systems and Unit Cells (45%), Voids (22%) and Crystal Defects (14%) of all Solid State questions.

Is the Solid State PYQ PDF free?

Yes. The PDF, the answer key and every step-by-step solution on PrepWiser are free, with no login needed to practise.

More Chemistry chapters

JEE Main PYQs by year: 2025 · 2024 · 2023 · 2022 · 2021 · 2020

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